The solution set for x(x+2)^2(x 1)^5(2x 3)(x 3)^4>or equal to 0 is given by x belongs to [a,b] union [c,infinity) then the value of a+B+C=______
![Factorise: (i) x^3 - 2x^2 - x + 2 (ii) x^3 - 3x^2 - 9x - 5 (iii) x^3 + 13x^2 + 32x + 20 (iv) 2y^3 + y^2 - 2y - 1 Factorise: (i) x^3 - 2x^2 - x + 2 (ii) x^3 - 3x^2 - 9x - 5 (iii) x^3 + 13x^2 + 32x + 20 (iv) 2y^3 + y^2 - 2y - 1](https://d138zd1ktt9iqe.cloudfront.net/media/seo_landing_files/output-onlinepngtools-1568203663.png)
Factorise: (i) x^3 - 2x^2 - x + 2 (ii) x^3 - 3x^2 - 9x - 5 (iii) x^3 + 13x^2 + 32x + 20 (iv) 2y^3 + y^2 - 2y - 1
![1)Știind că (x1^2-1)/x1+(x2^2-1)/x2=2, unde x1 și x2 sunt soluțiile ecuației x^2- mx −1= 0, aflati m - Brainly.ro 1)Știind că (x1^2-1)/x1+(x2^2-1)/x2=2, unde x1 și x2 sunt soluțiile ecuației x^2- mx −1= 0, aflati m - Brainly.ro](https://ro-static.z-dn.net/files/d88/df48c5365b6428d1184957958f152269.png)
1)Știind că (x1^2-1)/x1+(x2^2-1)/x2=2, unde x1 și x2 sunt soluțiile ecuației x^2- mx −1= 0, aflati m - Brainly.ro
![calculus - Don't understand why this binomial expansion is not valid for x > 1 - Mathematics Stack Exchange calculus - Don't understand why this binomial expansion is not valid for x > 1 - Mathematics Stack Exchange](https://i.stack.imgur.com/y9N06.png)
calculus - Don't understand why this binomial expansion is not valid for x > 1 - Mathematics Stack Exchange
![Se considera expresia E(x). arata ca (x+2)(2x-1)-x(x+3)+1=x^2-1, pentru orice x apartine R - YouTube Se considera expresia E(x). arata ca (x+2)(2x-1)-x(x+3)+1=x^2-1, pentru orice x apartine R - YouTube](https://i.ytimg.com/vi/zWlNk74sF2Y/maxresdefault.jpg)
Se considera expresia E(x). arata ca (x+2)(2x-1)-x(x+3)+1=x^2-1, pentru orice x apartine R - YouTube
![2. Se consideră expresia E(x) = (x - 1)² -(x-2)² + (1 - x)²- (2-x)², unde xeste număr real,a) Arată ca E(x) - Brainly.ro 2. Se consideră expresia E(x) = (x - 1)² -(x-2)² + (1 - x)²- (2-x)², unde xeste număr real,a) Arată ca E(x) - Brainly.ro](https://ro-static.z-dn.net/files/d65/1ea6afb4864cc58347d5d44387a6d522.jpg)
2. Se consideră expresia E(x) = (x - 1)² -(x-2)² + (1 - x)²- (2-x)², unde xeste număr real,a) Arată ca E(x) - Brainly.ro
![if e c are the distinct roots of the equation x2 x 1 0 then 101 107 is equal to 1 0 2 1 3 2 4 1 zjtkkayy -Maths - TopperLearning.com if e c are the distinct roots of the equation x2 x 1 0 then 101 107 is equal to 1 0 2 1 3 2 4 1 zjtkkayy -Maths - TopperLearning.com](https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=2ca4f90f94693292e5bf8c308dd28823.png&d=0)